Cardinal sequences of LCS spaces under GCH

Juan Carlos Martinez, Lajos Soukup

Let $ {\mathcal C}(\alpha)$ denote the class of all cardinal sequences of length $ \alpha$ associated with compact scattered spaces. Also put

$\displaystyle {\mathcal C}_{\lambda}(\alpha)=\{f\in {\mathcal C}(\alpha): f(0)={\lambda} = \min[
f({\beta}) : \beta < {\alpha}]\}.$

If $ {\lambda}$ is a cardinal and $ {\alpha}<{\lambda}^{++}$ is an ordinal, we define $ {\mathcal D}_{\lambda}(\alpha)$ as follows: if $ {\lambda}={\omega}$ ,

$\displaystyle {\mathcal D}_{\omega}(\alpha)=\{f\in
{}^{\alpha}\{{\omega},{\omega}_1\}: f(0)={\omega}\},
$

and if $ {\lambda}$ is uncountable,

\begin{multline}\notag
{\mathcal D}_{\lambda}({\alpha})=\{f\in
{}^{\alpha}\{{\la...
...t{ is $<{\lambda}$-closed and successor-closed in
${\alpha}$}
\}.
\end{multline}

We show that for each uncountable regular cardinal $ {\lambda}$ and ordinal $ {\alpha}<{\lambda}^{++}$ it is consistent with GCH that $ {\mathcal C}_{\lambda}(\alpha)$ is as large as possible, i.e.

$\displaystyle {\mathcal C}_{\lambda}(\alpha)={\mathcal D}_{\lambda}(\alpha).
$

This yields that under GCH for any sequence $ f$ of regular cardinals of length $ {\alpha}$ the following statements are equivalent:
(1)
$ f\in {\mathcal C}(\alpha)$ in some cardinal preserving and GCH-preserving generic-extension of the ground model.
(2)
for some natural number $ n$ there are infinite regular cardinals $ \lambda_0>\lambda_1>\dots>\lambda_{n-1}$ and ordinals $ {\alpha}_0,\dots, {\alpha}_{n-1}$ such that $ {\alpha}={\alpha}_0+\cdots+{\alpha}_{n-1}$ and $ f=f_0\mathop{{}^{\frown}\makebox[-3pt]{}}\
f_1\mathop{{}^{\frown}\makebox[-3pt]{}}\cdots \ \mathop{{}^{\frown}\makebox[-3pt]{}}f_{n-1}$ where each $ f_i\in{\mathcal D}_{\lambda_i}(\alpha_i)$ .

The proofs are based on constructions of universal locally compact scattered spaces.

Key words and phrases:locally compact scattered space, superatomic Boolean algebra, cardinal sequence, universal

2000 Mathematics Subject Classification: 54A25, 06E05, 54G12, 03E35, 03E05

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